APTITUDE-Problems on H.C.F AND L.C.M

H.C.F AND L.C.M

Facts And Formulae:

1.Highest Common Factor:(H.C.F) or Greatest Common Meaure(G.C.M) :

The H.C.F of two or more than two numbers is the greatest number that divides each of them exactly.
There are two methods :
1.Factorization method: Express each one of the given numbers as the product of prime factors.
The product of least powers of common prime factors gives HCF.
Example : Find HCF of 26 * 32*5*74 , 22 *35*52 * 76 , 2*52 *72
Sol: The prime numbers given common numbers are 2,5,7
Therefore HCF is 22 * 5 *72 .

2.Division Method : Divide the larger number by
smaller one. Now divide the divisor by remainder. Repeat the process
of dividing preceding number last obtained till zero is obtained as
number. The last divisor is HCF.

Example: Find HCF of 513, 1134, 1215
Sol:

1134) 1215(1
1134
———-
81)1134(14
81
———–
324
324
———–
0
———–
HCF of this two numbers is 81.

81)513(6
486
——–
27)81(3
81
—–
0

HCF of 81 and 513 is 27.

3.Least common multiple[LCM] : The least number which is divisible by each one of given numbers is LCM.
There are two methods for this:
1.Factorization method : Resolve each one into product of prime factors.
Then LCM is product of highest powers of all factors.

2.Common division method.

Problems:
1.The HCF of 2 numbers is 11 and LCM is 693.If one of numbers is 77.find other.
Sol: Other number = 11 * 693/77=99.

2.Find largest number of 4 digits divisible by 12,15,18,27

Sol: The largest number is 9999.
LCM of 12,15,18,27 is 540.
on dividing 9999 by 540 we get 279 as remainder.
Therefore number =9999 – 279 =9720.

3.Find least number which when divided by 20,25,35,40 leaves remainders 14,19,29,34.

Sol:

20–14=6
25-19=6
35-29=6
40-34=6

Therefore number =LCM of (20,25,35,40) – 6=1394
4.252 can be expressed as prime as :

2 252
2 126
3 63
3 21
7

prime factor is 2 *2 * 3 * 3 *7

5.1095/1168 when expressed in simple form is

1095)1168(1
1095
——
73)1095(15
73
———
365
365
———
0
———-
So, HCF is 73
Therefore
1095/1168 = 1095/73/1168/73= 15/16

6.GCD of 1.08,0.36,0.9 is
Sol:
HCF of 108,36,90

36)90(2
72
—-
18)36(2
36
—-
0
—-
HCF is 18.

HCF of 18 and 108 is 18
18)108(6
108
——-
0
——–
Therefore HCF =0.18

7.Three numbers are in ratio 1:2:3 and HCF is 12.Find numbers.
Sol:
Let the numbers be x.
Three numbers are x,2x,3x
Therefore HCF is

2x)3x(1
2x
—–
x)2x(2
2x
——–
0
————-

HCF is x so, x is 12
Therefore numbers are 12,24,36.

8.The sum of two numbers is 216 and HCF is 27.
Sol:
Let numbers are

27a + 27 b =216

a + b =216/27=8

Co-primes of 8 are (1,7) and (3,5) numbers=(27 * 1 ), (27 * 7)
=27,89

9.LCM of two numbers is 48..The numbers are in ratio 2:3.The sum of numbers is
Sol:
Let the number be x.
Numbers are 2x,3x
LCM of 2x,3x is 6x
Therefore
6x=48
x=8.
Numbers are 16 and 24
Sum=16 +24=40.

10.HCF and LCM of two numbers are 84 and 21.If ratio of two numbers is 1:4.Then largest of two numbers is

Sol:
Let the numbers be x,4x
Then x * 4x = 84 * 21
x2 =84 * 21 /4
x = 21
Largest number is 4 * 21.

11.HCF of two numbers is 23,and other factors of LCM are 13,14.Largest number is
Sol:
23 * 14 is Largest number.

12.The maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets same number of pens and pencils is ?
Sol:
HCF of 1001 and 910

910)1001(1
910
————
91)910(10
910
——–
0
———
Therefore HCF=91

13.The least number which should be added to 2497 so that sum is divisible by 5,6,4,3 ?
Sol: LCM of 5,6,4,3 is 60.
On dividing 2497 by 60 we get 37 as remainder.
Therefore number to added is 60 – 37 =23.
Answer is 23.

14.The least number which is a perfect square and is divisible by each of numbers 16,20,24 is ?
Sol: LCM of 16,20,24 is 240.

2 * 2*2*2*3*5=240
To make it a perfect square multiply by 3 * 5
Therefore 240 * 3 * 5=3600
Answer is 3600.

If you have questions, please ask below

27 thoughts on “APTITUDE-Problems on H.C.F AND L.C.M

    1. Jay

      LCM (6,8,12) = 24 it’s the smallest no exactly divisible by the 3 numbers

      the smallest 3 digit no. will be 24*5= 120
      (see 24*4= 96 a twoo digit no.)

      Reply
  1. sherry

    I have this problem to solve
    there are 2 race cars racing around a race track 1 race car takes 6 seconds the other takes
    61/2 seconds how long would it take race car(1) to meet up with race car (2) this is in hcf and lcm

    Reply
  2. priyanshu mohapatra

    sir,i have a problem
    what is lowest term of a fraction please clarify it.
    Is it necessary to take hcf to find the lowest term of fraction if so then why?

    Reply
  3. ANUJ ABHISHEK

    what is the greatest number when it is divided by 9 11 13 leaves a remainder of 1 2 3 respectively .????

    Reply

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